1π
β
One way to achieve this would be to create a helper method that returns the report
or the context needed by both the methods. The issue here is you are returning a HTTPResponse
object, and it is cleanest to use helper method here:
def get_report(request):
report=Report.objects.filter(report=report_id)
#do more processing here.
#returning a dict is probably safest here, because, in the calling method, `.get()` would not throw an error if key is not present.
return {'report': report, 'somevar': somevar}
def followup(request):
marklist = get_report(request).get('somevar')
return render(request, 'incident/followup.html',{'somevar':marklist})
def report_template(request):
report = get_report(request).get('report')
return render(request, 'incident/print.html',
{'report':report})
π€karthikr
0π
You can not do that with views, you have to look up for templatetags, which is a better way to do so in Django (a view accepts a Request argument and returns an HttpResponse variable).
See https://docs.djangoproject.com/en/dev/howto/custom-template-tags/.
Using templatetags makes your code reusable, by factoring what you do in views.
π€Gabriel Pichot
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Source:stackexchange.com