11👍
I’ve also been having an issue where I need a max value object of a related set, but I require the entire object. I have not been able to figure out a solution using annotation and Case. Until I do, I use this prefetching solution. If each city does not have a large amount of census objects, or if your application is not performance bound, this may work for you.
inner_qs = Census.objects.order_by('-date')
cities = City.objects.prefetch_related(Prefetch("census_set", queryset=inner_qs, to_attr="census_list"))
class City(models.Model):
@property
def latest_census(self):
if hasattr(self, 'census_list') and len(self.census_list) > 0:
return self.census_list[0]
return None
If this does not work for you, consider some of the suggestions found here:
http://blog.roseman.org.uk/2010/08/14/getting-related-item-aggregate/
5👍
At this moment, they are not a django query expression to annotate a not aggregated field from a related 1:N model based on a sql having expression.
You can accomplish it with several workarounds like split query and work with data in memory ( itertools groupby f.e. ) or through raw queries. But this will not match your requirements performance and database agnostic.
I explain here what I will do if this was my app. For developers is hard to have redundancy in database. In your scenario, last census
by city
is a calculated field … but, in this case, take in consideration to materialize last_census
:
The dirty work …
class City(models.Model):
last_census = models.ForeignKey('Census', null=True,
blank=True, editable=False)
...
For easy maintenance, you can overrite save
and delete
methods on Census
to keep last_census
up to date.
class Census(models.Model):
...
#overriding save
def save(self, *args, **kwargs):
super(Census, self).save(*args, **kwargs)
#updating last_census on referenced city
max_census = Census.objects.filter( city = self.city ).latest('date')
self.city.last_census = max_census.city if max_census else None
self.city.save()
#overriding delete
def delete(self, *args, **kwargs):
#updating last_census on referenced city
max_census = ( Census.objects
.filter( city = self.city )
.exclude( id = self.id )
.latest('date') )
self.city.last_census = max_census.city if max_census else None
self.city.save()
super(Census, self).delete(*args, **kwargs)
Notice: if you are more comfortable, you can code it with signals ( pre_delete, post_save, … ) instead overriding methods.
The best …
Your query now:
City.objects.select_related('last_census__value').all()
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2👍
Something like this may work for you:
I have this to show last reservation for restaurants
Reservation.objects.filter(
restaurant__city_id__gt=0
).distinct().annotate(city_count=Count(
'restaurant_id')
).order_by('-reservationdate').filter(city_count__gte=1)[:20]
in your case it may be something like:
city = Census.objects.filter(
city_id__gt=0
).distinct().annotate(city_count=Count(
'city_id')
).order_by('-date').filter(city_count__gte=1)[:20]
and your html
{% for city in city %}
{{ city.city.name }} {{ city.date }}<br>
{% endfor %}
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2👍
It’s late and I’m getting hungry so I see won’t this all the way through*, but the following code will return the latest census value in a valueset for a given city. A queryset might be possible, but again I am hungry!
*I wasn’t sure if you needed to retrieve all of the latest values for all cities or a specific city. The latter is pretty easy, the former is a bit harder. You could easily put this as a method on your model and call it on every city in a loop inside of a template/view.
Hope this helps!
from app.models import *
from django.db.models import F
City.objects.annotate(
values=F("census__value"),
date=F("census__date"))\
.values('values', 'name').filter(name="Atlanta")\
.latest('date')
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