[Django]-Altering one query parameter in a url (Django)

20👍

✅

So, write a template tag around this:

from urlparse import urlparse, urlunparse
from django.http import QueryDict

def replace_query_param(url, attr, val):
    (scheme, netloc, path, params, query, fragment) = urlparse(url)
    query_dict = QueryDict(query).copy()
    query_dict[attr] = val
    query = query_dict.urlencode()
    return urlunparse((scheme, netloc, path, params, query, fragment))

For a more comprehensive solution, use Zachary Voase’s URLObject 2, which is very nicely done.

Note:
The urlparse module is renamed to urllib.parse in Python 3.

👤Tom Christie

[Django]-PyCharm: DJANGO_SETTINGS_MODULE is undefined

26👍

I did this simple tag which doesn’t require any extra libraries:

@register.simple_tag
def url_replace(request, field, value):

    dict_ = request.GET.copy()

    dict_[field] = value

    return dict_.urlencode()

Use as:

<a href="?{% url_replace request 'param' value %}">

It wil add ‘param’ to your url GET string if it’s not there, or replace it with the new value if it’s already there.

You also need the RequestContext request instance to be provided to your template from your view. More info here:

http://lincolnloop.com/blog/2008/may/10/getting-requestcontext-your-templates/

👤mpaf

10👍

I improved mpaf’s solution, to get request directly from tag.

@register.simple_tag(takes_context = True)
def url_replace(context, field, value):
    dict_ = context['request'].GET.copy()
    dict_[field] = value
    return dict_.urlencode()

👤whncode

4👍

This worked pretty well for me. Allows you to set any number of parameters in the URL. Works nice for a pager, while keeping the rest of the query string.

from django import template
from urlobject import URLObject

register = template.Library()

@register.simple_tag(takes_context=True)
def url_set_param(context, **kwargs):
    url = URLObject(context.request.get_full_path())
    path = url.path
    query = url.query
    for k, v in kwargs.items():
        query = query.set_param(k, v)
    return '{}?{}'.format(path, query)

Then in the template:

<a href="{% url_set_param page=last %}">

👤allanberry

1👍

There are a number of template tags for modifying the query string djangosnippets.org:

http://djangosnippets.org/snippets/553/
http://djangosnippets.org/snippets/826/
http://djangosnippets.org/snippets/1243/

I would say those are the most promising looking. One point in all of them is that you must be using django.core.context_processors.request in your TEMPLATE_CONTEXT_PROCESSORS.

👤Mark Lavin

0👍

You can try https://github.com/dcramer/django-paging

👤Igor

0👍

In addition to the snippets mentioned by Mark Lavin, Here’s a list of other implementations I could find for a Django template tag which modifies the current HTTP GET query string.

On djangosnippets.org:

On PyPI: