3👍
You need return in anwer – JSON
For example
def answer(request):
# same you code
payload = {'success': True}
return HttpResponse(json.dumps(payload), content_type='application/json')
2👍
In the jQuery.ajax
docs I can read this:
Deprecation Notice: The jqXHR.success(), jqXHR.error(), and jqXHR.complete() callbacks are deprecated as of jQuery 1.8. To prepare your code for their eventual removal, use jqXHR.done(), jqXHR.fail(), and jqXHR.always() instead.
So, I would follow the example there and try if this works instead:
// Assign handlers immediately after making the request,
// and remember the jqxhr object for this request
var jqxhr = $.ajax( "example.php" )
.done(function() { alert("success"); })
.fail(function() { alert("error"); })
.always(function() { alert("complete"); });
// perform other work here ...
// Set another completion function for the request above
jqxhr.always(function() { alert("second complete"); });
Adapted to your code, it may look like this:
var jqxhr = $.ajax( "/eventsearch/eventsearch/createCustom/", {
data: {name: name, loc: loc, start: start, end: end, tags: tags, event_id: event, profile: user}
})
.done(function() { alert("success"); })
.fail(function() { alert("error"); })
.always(function() { alert("complete"); });
I’m not completely sure about data, I was just following the docs.
Also, it should be good to add mimetype
to the response like this:
return HttpResponse('', mimetype="application/json")
I think I’ve read somewhere that Ajax won’t work if this is not set with Django, I don’t remember where, I’m trying to find it on Google, give it a try.
Hope this helps!
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Source:stackexchange.com