[Solved]-Using django how can I combine two queries from separate models into one query?

by

11👍

✅

I would suggest that you use Model inheritance.

Create a base model that contains date and title. Subclass Msg1 and Msg2 off it as described. Do all your queries (to fill a page) using the base model and then switch to the derived type at the last moment.

The really great thing about inheritance is that django then allows you to use the base model in foreign keys from other models, so you can make your whole application more flexible. Under the hood it is just a table for the base model with a table per sub-model containing one-to-one keys.

👤Tom Leys

2👍

“combine these two queries into one query, sort it by date, and paginate it?”

  1. That’s the SQL union. Leave the Django ORM and use a SQL union. It’s not brilliantly fast because SQL has to create a temporary result, which it sorts.

  2. Create the temporary result, which can be sorted. Since a list has a sort method, you’ll have to merge the two results into one list.

  3. Write a merge algorithm that accepts two query sets, paginating the results.

Edit. Here’s a merge algorithm.

def merge( qs1, qs2 ):
    iqs1= iter(qs1)
    iqs2= iter(qs2)
    k1= iqs1.next()
    k2= iqs2.next()
    k1_data, k2_data = True, True
    while k1_data or k2_data:
        if not k2_data:
            yield k1
            try:
                k1= iqs1.next()
            except StopIteration:
                k1_data= False
        elif not k1_data:
            yield k2
            try:
                k2= iqs2.next()
            except StopIteration:
                k2_data= False
        elif k1.key <= k2.key:
            yield k1
            try:
                k1= iqs1.next()
            except StopIteration:
                k1_data= False
        elif k2.key < k1.key: # or define __cmp__.
            yield k2
            try:
                k2= iqs2.next()
            except StopIteration:
                k2_data= False
        else:
            raise Exception( "Wow..." )

You can fold in pagination:

def paginate( qs1, qs2, start=0, size=20 ):
    count= 0
    for row in merge( qs1, qs2 ):
        if start <= count < start+size:
            yield row
        count += 1
        if count == start+size:
            break
👤S.Lott

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