[Fixed]-In django, values(*field) doesn't give all values of ForeignKey field with sliced queryset

That’s how list slicing works, [:1] means [0:1] (from index 0 to index 1) with 1 is not included:

>>> my_list = [1, 2, 3]
>>> my_list
[1, 2, 3]
>>> my_list[:1]
[1]
>>> my_list[0:1]
[1]

SomeModel.objects.filter(pk__gte=2)[:1] means you’re slicing a QuerySet and the result is list of model instances.

SomeModel.objects.filter(pk__gte=2).values('name')[:1] means you’re slicing a ValuesQuerySet and the result is list of dictionaries.

Look at the following examples:

>>> from polls.models import Question
>>> 
>>> Question.objects.all()
[<Question: q1>, <Question: q2>, <Question: q3>]
>>> Question.objects.filter(pk__gte=2)  # returns QuerySet
[<Question: q2>, <Question: q3>]
>>> Question.objects.filter(pk__gte=2)[:1]  # slicing a QuerySet
[<Question: q2>]  # list of Question instances
>>> 
>>> Question.objects.filter(pk__gte=2).values('question_text')  # returns ValuesQuerySet
[{'question_text': u'q2'}, {'question_text': u'q3'}]
>>> Question.objects.filter(pk__gte=2).values('question_text')[:1]  # slicing a ValuesQuerySet
[{'question_text': u'q2'}]  # list of dictionaries

Note: SomeModel.objects.filter(pk=2) would always return a QuerySet that contains 1 object (with pk=2 in this case).