[Answer]-Result.ready() isn't work as expected in django celery?

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  1. When you call file.delay, celery queues up the task to run in the background, at some later point.

  2. If you immediately check result.successful(), it’ll be false, as the task hasn’t run yet.

If you need to chain tasks (one firing after another) use Celery’s workflow solutions (in this case chain):

def do_this(password, source12, destination):
    chain = file.s(password, source12, destination) | save_to_database.s()
    chain()


@celery.task()
def file(password, source12, destination):
    foo = password
    return foo


@celery.task()
def save_to_database(foo):
    Foo.objects.create(result=foo)
👤Jack Shedd

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