[Answer]-Assign value to variable from database content in Django

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1👍

✅

Your showopen variable isn’t in the four options provided by your code. If you don’t have a debugger to see what the variable actually is, then add some print statements to your code that print the variable to the console.

update_grp = User_Groups.objects.get(user_id=request.user.id)
    showopen = update_grp.profilegroup
    print showopen
    #..
👤Aidan Ewen

0👍

You’re missing an ‘else’ clause so the interpretator sees there could be a case where ‘slidercategory’ isn’t available within the scope of your function (where non of the if statements are matched).

Either add an else clause or assign sliderproduct = ‘somedefaultvalue’ at the top of your function, another solution would be to move the return bar into the if clauses their scopes, which would result in a None being returned when none of the ifs are matched.

>>> def test(foo):
...     if foo == 2:
...        bar = 'hello'
...     elif foo == 3:
...        bar = 'goodbye'
...     return bar
>>> test(2)
>>> 'hello'
>>> test(1)
UnboundLocalError: local variable 'bar' referenced before assignment
👤Hedde van der Heide

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