[Answer]-Django To Filter distinct content with counts

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1👍

✅

You can do this:

from django.db.models import Count
jobs.objects.values('states').annotate(count=Count('states'))
👤Akshar Raaj

0👍

It seems to be tricky, but u can do this by refer “https://docs.djangoproject.com/en/dev/ref/models/querysets/“

👤USER

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