1đź‘Ť
âś…
First, in this line
if not Pupil.objects.filter(name=name):
It looks like the name
variable is undefined no ?
Then here is a shortcut for your code I think:
def update_pupils(teacher, updated_list):
# Step 1 : delete
Pupil.objects.filter(teacher=teacher).exclude(name__in=updated_list).delete() # delete all the not updated objects for this teacher
# Step 2 : update
# either
for name in updated_list:
Pupil.objects.update_or_create(name=name, defaults={teacher:teacher}) # for updated objects, if an object of this name exists, update its teacher, else create a new object with the name from updated_list and the input teacher
# or (but I'm not sure this one will work)
Pupil.objects.update_or_create(name__in=updated_list, defaults={teacher:teacher})
Another solution, if your Pupil object only has those 2 attributes and isn’t referenced by a foreign key in another relation, is to delete all the “Pupil” instances of this teacher, and then use a bulk_create.. It allows only 2 access to the DB, but it’s ugly
EDIT: in first loop, pupil
also is undefined
👤Ricola3D
Source:stackexchange.com