[Answer]-How to construct a get_admin_url / get app_label and class name?

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1👍

✅

You can use the Reversing admin URLs feature

from django.core import urlresolvers
c = Choice.objects.get(...)
change_url = urlresolvers.reverse('admin:polls_choice_change', args=(c.id,))

If you wish to refer the change_list page, you would do

urlresolvers.reverse('admin:%s_%s_changelist' % (app_label, model_name))
👤karthikr

0👍

It’s also possible to set app_name and model_name with ContentType see: https://stackoverflow.com/a/11395481/991572

So I ended up doing this in webapp/models.py:

from django.contrib.contenttypes.models import ContentType
from django.core import urlresolvers

class Base(models.Model):
    title = models.CharField(max_length=100)

    def _get_admin_url(self):
        "Returns the admin change view url."
        content_type = ContentType.objects.get_for_model(self.__class__)
        view_name = "admin:%s_%s_change" % (content_type.app_label, content_type.model)
        url = urlresolvers.reverse(view_name, args=(self.id,)) 
        return url

    admin_url = property(_get_admin_url)            

class Book(Base):
    something = models.CharField(max_length=100)

Register Base and Book to the admin site, created some entries and in shell:

In [1]: from webapp.models import *

In [2]: Base.objects.get(pk=1).admin_url
Out[2]: '/admin/webapp/base/1/'

In [3]: Book.objects.get(pk=2).admin_url
Out[3]: '/admin/webapp/book/2/'
👤allcaps

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