1👍
✅
Without any additional libraries, something like this:
(1) get the data from the table
function getTableData()
{
// Array of data we'll return
var data = [];
// Counter
var i = 0;
// Cycle through each of the table body's rows
$('tbody tr').each(function(index, tr) {
var tds = $(tr).find('td');
// Check we've got two <td>s
if (tds.length > 1) {
// If we do, get their text content and add it to the data array
data[i++] = {
email: tds[0].textContent,
password: tds[1].textContent
}
}
});
return data;
}
(2) post it to the server
$.ajax({
method: 'post',
url: '', // Set the URL of whatever in Django will handle your post
data: getTableData()
});
However, if I were attempting this task, I would achieve (1) by using Knockout, which would allow for a much better separation between view and viewmodel (or between template and view, you might think of them, as a Django user). Great that you’re using a decent server-side framework, would be a pity to end up with spaghetti code on the client!
Source:stackexchange.com