[Answer]-How to create a ListView with an argument | Django 1.6?

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Actually what you probably want is a DetailView for Categories (then iterate over content in the template). E.g.

url(r'^category/$', CategoryListView.as_view()),
url(r'^category/(?P<slug>[\w-]+)/$', CategoryDetailView.as_view()),

If you want subcategory features or use detail views as list views, either add a queryset to context or change the view’s flow (you’re probably better of creating a custom view for the latter).

👤Hedde van der Heide

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