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Sounds like you have to use AJAX for this. You can define a Django view which returns a JSON message with something like:
{
status: "ok",
url: "img1.jpg"
}
So in your code, you can define an event handler (in JavaScript) with something like this:
// Attach a listener to a button for a click event,
document.getElementById("testImageButton").addEventListener("click", function() {
var xhr = new XMLHttpRequest();
// This URL returns the above JSON.
xhr.open("GET", "/images/random");
xhr.onloadend = function() {
// Should have error handling in case response does not return correctly.
var imageResult = JSON.parse(xhr.response);
if(imageResult['status'] == 'ok') {
// update the image src
document.getElementById("testImage").setAttribute("src", imageResult['url']);
}
}
xhr.send()
})
So the only “dynamic function part” is whatever is inside your Django view function.
👤Viktor Chynarov
Source:stackexchange.com