1👍
✅
Create a template filter for splitting the list into chunks:
from django import template
register = template.Library()
@register.filter
def chunks(l, n):
n = max(1, int(n))
return (l[i:i+n] for i in xrange(0, len(l), n))
Usage:
{% for chunk in images|chunks:2 %}
<div class="row">
{% for image in chunk %}
<div class="col-sm-6">
# Add image/ or data you want
</div>
{% endfor %}
</div>
{% endfor %}
You could also split the list into chunks before sending it to the template.
More on how to split lists into chunks here:
How do you split a list into evenly sized chunks?
Custom filters for padding lists:
@register.filter
def ljust_list(l, n):
"""
ljust_list([1, 2], 4) -> [1, 2, None, None]
"""
return l + [None] * (n - len(l))
@register.filter
def rjust_list(l, n):
"""
rjust_list([1, 2], 4) -> [None, None, 1, 2]
"""
return [None] * (n - len(l)) + l
Usage:
{% for chunk in images|chunks:2 %}
<div class="row">
{% for image in chunk|ljust_list:2 %}
<div class="col-sm-6">
# Add image/ or data you want
</div>
{% endfor %}
</div>
{% endfor %}
1👍
This works:
{% for obj in objects %}
{% if not forloop.counter|divisibleby:2 and forloop.last %}
<div class="row">
<div class="col-md-6">
{{ obj }}
</div>
</div>
{% elif not forloop.counter|divisibleby:2 %}
<div class="row">
<div class="col-md-6">
{{ obj }}
</div>
{% elif forloop.counter|divisibleby:2 %}
<div class="col-md-6">
{{ obj }}
</div>
</div>
{% endif %}
{% endfor %}
This solution uses Django built-in tags and filters. You may consider creating a custom tag, but that goes beyond the scope of the question.
Django: For Loop, Custom Tags
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Source:stackexchange.com