[Answered ]-Rounding a timedelta to the nearest 15 minutes

2๐Ÿ‘

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I ended up creating my own solution as I didnโ€™t find another way

def round_timedelta(td, period):
    """
    Rounds the given timedelta by the given timedelta period
    :param td: `timedelta` to round
    :param period: `timedelta` period to round by.
    """
    period_seconds = period.total_seconds()
    half_period_seconds = period_seconds / 2
    remainder = td.total_seconds() % period_seconds
    if remainder >= half_period_seconds:
        return timedelta(seconds=td.total_seconds() + (period_seconds - remainder))
    else:
        return timedelta(seconds=td.total_seconds() - remainder)

Used in iPython:

In [4]: print round_timedelta(timedelta(hours=1, minutes=27), timedelta(minutes=15))
1:30:00

In [5]: print round_timedelta(timedelta(hours=1, minutes=30), timedelta(minutes=15))
1:30:00

In [6]: print round_timedelta(timedelta(hours=1, minutes=31), timedelta(minutes=15))
1:30:00

In [7]: print round_timedelta(timedelta(hours=1, minutes=37), timedelta(minutes=15))
1:30:00

In [8]: print round_timedelta(timedelta(hours=1, minutes=38), timedelta(minutes=15))
1:45:00
๐Ÿ‘คInti

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