[Answered ]-Django ajax follow and unfollow

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2👍

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def user_follow(request):
    user_id = request.POST.get('id', None)
    action = request.POST.get('action', '')

    FOLLOW_ACTION = 'follow'
    UNFOLLOW_ACTION = 'unfollow'

    if request.user.is_anonymous:
        return JsonResponse({
            'status':'ko',
            'message': 'You must login'}
        )

    if action not in [FOLLOW_ACTION, UNFOLLOW_ACTION]:
        return JsonResponse({
            'status':'ko',
            'message': 'Unknown action {}'.format(action)}
        )

    try:
        user = User.objects.get(id=user_id)
        if action == UNFOLLOW_ACTION:
            Contact.objects.filter(user_from=request.user,user_to=user).delete()
            return JsonResponse({
                'status':'ok'
                })
        else:
            contact, created = Contact.objects.get_or_create( user_from=request.user, user_to=user)
            return JsonResponse({
                'status':'ok',
                'message': 'Following id : {}'.format(contact.id)
            })


    except User.DoesNotExist:
        return JsonResponse({
            'status':'ko'
            'message': 'user id: does not exist: {}'.format(user_id)
        })

You mixed up follow and unfollow, when action is unfollow you create contact.

Template:

{% if request.user != user %}
  <a> Follow ....
{% endif %}
👤user2021091

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