[Django]-Copy file into another folder with django?

by

2👍

✅

By looking at Django docs what you get when you do img = request.FILES['avatar'] is a file descriptor that points to an open file with your image.

Then you should to dump the contents in your actual avatar path, right?

#Here is where I create the name of the path to save as a VARCHAR field, THIS WORKS TOO
avatar = "../../static/profile/" + str(request.session['user_id']) + "/" + str(img)
# # # # # 
with open(avatar, 'wb') as actual_file:
    actual_file.write(img.read())
# # # # #    
return redirect(request, 'myapp/upload.html')

Beware: the code is untested.

👤Savir

3👍

You can pass a callable to upload_to. Basically, what it means is whatever value that callable returns, the image will be uploaded in that path.

Example:

def get_upload_path(instance, filename):
    return "%s/%s" % (instance.user.id, filename)

class MyModel:
    user = ...
    image = models.FileField(upload_to=get_upload_path)

There’s more information in the docs and an example too, though similar to what I posted above.

👤xyres

0👍

from django.shortcuts import render
from django.conf import settings
from django.core.files.storage import FileSystemStorage



def uploadimage(request):
    if request.method == 'POST' and request.FILES['avatar']:
        img = request.FILES['avatar']
        fs = FileSystemStorage()

        #To copy image to the base folder 
        #filename = fs.save(img.name, img)     

        #To save in a specified folder
        filename = fs.save('static/profile/'+img.name, img)
        uploaded_file_url = fs.url(filename)                 #To get the file`s url
        return render(request, 'myapp/upload.html', {
            'uploaded_file_url': uploaded_file_url
        })
     return render(request, 'myapp/upload.html')
👤Merrin K

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