[Django]-Python conditionally round up numbers

by

2👍

✅

def round_up(value, multiple):
    return multiple * math.ceil(float(value) / multiple)

def digits(value):
    return int(math.log(value, 10)) + 1

def round_price(value):
    if value < 10000:
        return int(round_up(value, 1000))
    d = digits(value)
    new_value = int(round_up(value, 10 ** (d - 2)))
    new_value -= 10 ** (d - 3)
    return new_value
👤Mark Ransom

5👍

import math
roundup = lambda x: math.ceil(x/1000.0) * 1000

Although rounding 353990 to 359000 makes no sense. This function will round 353990 up to 354000.

If you want normal rounding rather than a ’round up’, you would just use the builtin funciton round:

round(x, -3)

and so for a generic roundup with the same function signature as round

def roundup(x, n=0):
    return math.ceil(x * (10**n)) * (10**-n)
👤forivall

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