[Django]-How to get the path of the function call in Python?

4👍

The Zen of Python says: Explicit is better than implicit.

Why not call it like this: your.autodiscover(__file__), or even your.autodiscover(dirname(__file__)). That way, someone who reads your code doesn’t have to look for the magic in your autodiscover function, or look it up in the documentation.

👤sk1p

4👍

Using traceback.

Here’s one way I found to do that:

import traceback
def get_caller_filename():
   # last element ([-1]) is me, the one before ([-2]) is my caller. The first element in caller's data is the filename
   return traceback.extract_stack()[-2][0]
👤shx2

Leave a comment