7👍
✅
If you know you’re passing in N pks, then a count() query filtered by those pks should have exactly N results.
def do_exist(model, pks):
return model.objects.filter(pk__in=pks).count() == len(pks)
👤AKX
1👍
qs = MyModel.objects.filter(id__in=pks)
This gives you a queryset that you can apply .all() etc to
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Source:stackexchange.com