[Django]-How to pass special characters in the urls in django

The existing answer is missing a couple things, but I don’t have enough rep to comment or edit it. Here is a working solution:

For function based views:

In views.py:

# this is incorrect for current versions of Django in the other answer
from urllib.parse import unquote

def profile(request, user_name):
    user = User.objects.get(username=unquote(user_name))
    return render(request, 'user_profile.html', {'user':user})

Then, in urls.py, we can skip regex altogether:

from django.urls import path
urlpatterns = [
    path('users/<str:user_name>/', views.profile, name='profile'),
    # ... put more urls here...
]

That’s pretty much it for function based views. But I am using class based views, which look a tiny bit different. Here is what I did to get this working with class based views:

In views.py:

from urllib.parse import unquote
from django.views.generic import DetailView

class Profile(DetailView):
    """Display the user's profile"""
    template_name = 'user_profile.html'
    model = User

    def dispatch(self, request, *args, **kwargs):
        self.username = kwargs['user_name']
        return super().dispatch(request, *args, **kwargs)

    def get_object(self, *args, **kwargs):
        try:
            return User.objects.get(username=unquote(self.username))
        except:
            raise Http404

And when using class based views, your urls.py:

from django.urls import path
urlpatterns = [
    path('users/<str:user_name>/', views.Profile.as_view(), name='profile'),
    # ... put more urls here...
]

Specify the string by using w

url(r'^url_name/(?P<param_name>[\w\@%-+]+)/$',url_method,name='end_point_name')