[Django]-How can i find if the date lies between two dates

by

8👍

✅

Dates in the form YYYY-MM-DD can be compared alphabetically as well:

'2013-11-11' < '2013-11-15' < '2013-11-23'

date['min'] < your_date < date['max']

This won’t work correctly for other formats, such as DD.MM.YYYY or MM/DD/YYYY. In that case you have to parse the strings and convert them into datetime objects.

If don’t know whether the min/max variables are present, you can do:

date.get('min', '0000-00-00') < your_date < date.get('max', '9999-99-99')

and replace the default text values with anything you prefer.

👤eumiro

2👍

I think simple comparison works for that.

>>> from datetime import timedelta, date
>>> min_date = date.today()
>>> max_date = date.today() + timedelta(days=7)
>>> d1 = date.today() + timedelta(days=1)
>>> d2 = date.today() + timedelta(days=10)
>>> min_date < d1 < max_date
True
>>> min_date < d2 < max_date
False

Here is the updated version:

def is_in_range(d, min=date.min, max=date.max):
    if max:
        return min < d < max
    return min < d


print is_in_range(d1, min_date, max_date)
print is_in_range(d2, min_date, max_date)
print is_in_range(d1, min_date)
print is_in_range(d2, min_date)

True
False
True
True
👤Asterisk

1👍

If you deal with date objects:

from datetime import date
in_range = (first_date or date.min) < my_date < (second_date or date.max)
👤Don

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