[Django]-How to POST the data from a modal form of Bootstrap?

22👍

You need to handle it via ajax submit.

Something like this:

$(function(){
    $('#subscribe-email-form').on('submit', function(e){
        e.preventDefault();
        $.ajax({
            url: url, //this is the submit URL
            type: 'GET', //or POST
            data: $('#subscribe-email-form').serialize(),
            success: function(data){
                 alert('successfully submitted')
            }
        });
    });
});

A better way would be to use a django form, and then render the following snippet:

<form>
    <div class="modal-body">
        <input type="email" placeholder="email"/>
        <p>This service will notify you by email should any issue arise that affects your plivo service.</p>
    </div>
    <div class="modal-footer">
        <input type="submit" value="SUBMIT" class="btn"/>
    </div>
</form>

via the context – example : {{form}}.

8👍

I was facing same issue not able to post form without ajax.
but found solution , hope it can help and someones time.

<form name="paymentitrform" id="paymentitrform" class="payment"
                    method="post"
                    action="abc.php">
          <input name="email" value="" placeholder="email" />
          <input type="hidden" name="planamount" id="planamount" value="0">
                                <input type="submit" onclick="form_submit() " value="Continue Payment" class="action"
                                    name="planform">

                </form>

You can submit post form, from bootstrap modal using below javascript/jquery code :
call the below function onclick of input submit button

    function form_submit() {
        document.getElementById("paymentitrform").submit();
   }  

4👍

You CAN include a modal within a form. In the Bootstrap documentation it recommends the modal to be a “top level” element, but it still works within a form.

You create a form, and then the modal “save” button will be a button of type=”submit” to submit the form from within the modal.

<form asp-action="AddUsersToRole" method="POST" class="mb-3">

    @await Html.PartialAsync("~/Views/Users/_SelectList.cshtml", Model.Users)

    <div class="modal fade" id="role-select-modal" tabindex="-1" role="dialog" aria-labelledby="role-select-modal" aria-hidden="true">
        <div class="modal-dialog" role="document">
            <div class="modal-content">
                <div class="modal-header">
                    <h5 class="modal-title" id="exampleModalLabel">Select a Role</h5>
                </div>
                <div class="modal-body">
                    ...
                </div>
                <div class="modal-footer">
                    <button type="submit" class="btn btn-primary">Add Users to Role</button>
                    <button type="button" class="btn btn-secondary" data-dismiss="modal">Cancel</button>
                </div>
            </div>
        </div>
    </div>

</form>

You can post (or GET) your form data to any URL. By default it is the serving page URL, but you can change it by setting the form action. You do not have to use ajax.

Mozilla documentation on form action

👤Jess

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