[Django]-How can I return HTTP status code 204 from a Django view?

When using render, there is a status keyword argument.

return render(request, 'template.html', status=204)

(Note that in the case of status 204 there shouldn’t be a response body, but this method is useful for other status codes.)

Either what Steve Mayne answered, or build your own by subclassing HttpResponse:

from django.http import HttpResponse

class HttpResponseNoContent(HttpResponse):
    status_code = 204

def my_view(request):
    return HttpResponseNoContent()

The other answers work mostly, but they do not produce a fully compliant HTTP 204 responses, because they still contain a content header. This can result in WSGI warnings and is picked up by test tools like Django Web Test.

Here is an improved class for a HTTP 204 response that is compliant. (based on this Django ticket):

from django.http import HttpResponse

class HttpResponseNoContent(HttpResponse):
    """Special HTTP response with no content, just headers.

    The content operations are ignored.
    """

    def __init__(self, content="", mimetype=None, status=None, content_type=None):
        super().__init__(status=204)

        if "content-type" in self._headers:
            del self._headers["content-type"]

    def _set_content(self, value):
        pass

    def _get_content(self, value):
        pass

def my_view(request):
    return HttpResponseNoContent()