[Django]-Using {% url ??? %} in django templates

The selected answer is out of date and no others worked for me (Django 1.6 and [apparantly] no registered namespace.)

For Django 1.5 and later (from the docs)

Warning
Don’t forget to put quotes around the function path or pattern name!

With a named URL you could do:

(r'^login/', login_view, name='login'),
...
<a href="{% url 'login' %}">logout</a>

Just as easy if the view takes another parameter

def login(request, extra_param):
...
<a href="{% url 'login' 'some_string_containing_relevant_data' %}">login</a>

Make sure (django 1.5 and beyond) that you put the url name in quotes, and if your url takes parameters they should be outside of the quotes (I spent hours figuring out this mistake!).

{% url 'namespace:view_name' arg1=value1 arg2=value2 as the_url %}
<a href="{{ the_url }}"> link_name </a>

The url template tag will pass the parameter as a string and not as a function reference to reverse(). The simplest way to get this working is adding a name to the view:

url(r'^/logout/' , logout_view, name='logout_view')

I run into same problem.

What I found from documentation, we should use namedspace.

in your case {% url login:login_view %}

Judging from your example, shouldn’t it be {% url myproject.login.views.login_view %} and end of story? (replace myproject with your actual project name)

For example, there are 4 views in my_app1/views.py as shown below. *You can see the doc explaining URL namespaces in detail:

# "my_app1/views.py"

from django.shortcuts import render
from django.http import HttpResponse

def index(request):
    return render(request, 'index.html')

def test1(request):
    return HttpResponse("Test1")

def test2(request):
    return HttpResponse("Test2")

def test3(request):
    return HttpResponse("Test3")

And, there are 2 paths in my_app1/urls.py as shown below:

# "my_app1/urls.py"

from django.urls import path
from . import views

app_name = "my_app1"

urlpatterns = [
    path('test1/', views.test1, name="test1"),
    path('test2/', views.test2, name="test2"),
]

And, there are 4 paths in core/urls.py as shown below:

# "core/urls.py"

from django.contrib import admin
from django.urls import path, include
from my_app1 import views

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', views.index),
    path('my_app1/', include('my_app1.urls')),
    path('test3/', views.test3, name='test3'),
]

Now, you can set these URL namespaces to url tag in index.html as shown below:

{% "index.html" %}

<a href="{% url 'admin:index' %}">Admin</a>
<a href="{% url 'my_app1:test1' %}">Test1</a>
<a href="{% url 'my_app1:test2' %}">Test2</a>
<a href="{% url 'test3' %}">Test3</a>