[Django]-Django URLs TypeError: view must be a callable or a list/tuple in the case of include()

by

271👍

✅

Django 1.10 no longer allows you to specify views as a string (e.g. 'myapp.views.home') in your URL patterns.

The solution is to update your urls.py to include the view callable. This means that you have to import the view in your urls.py. If your URL patterns don’t have names, then now is a good time to add one, because reversing with the dotted python path no longer works.

from django.conf.urls import include, url

from django.contrib.auth.views import login
from myapp.views import home, contact

urlpatterns = [
    url(r'^$', home, name='home'),
    url(r'^contact/$', contact, name='contact'),
    url(r'^login/$', login, name='login'),
]

If there are many views, then importing them individually can be inconvenient. An alternative is to import the views module from your app. 

from django.conf.urls import include, url

from django.contrib.auth import views as auth_views
from myapp import views as myapp_views

urlpatterns = [
    url(r'^$', myapp_views.home, name='home'),
    url(r'^contact/$', myapp_views.contact, name='contact'),
    url(r'^login/$', auth_views.login, name='login'),
]

Note that we have used as myapp_views and as auth_views, which allows us to import the views.py from multiple apps without them clashing.

See the Django URL dispatcher docs for more information about urlpatterns.

👤Alasdair

3👍

This error just means that myapp.views.home is not something that can be called, like a function. It is a string in fact. While your solution works in django 1.9, nevertheless it throws a warning saying this will deprecate from version 1.10 onwards, which is exactly what has happened. The previous solution by @Alasdair imports the necessary view functions into the script through either
from myapp import views as myapp_views or
from myapp.views import home, contact

👤hAcKnRoCk

2👍

You may also get this error if you have a name clash of a view and a module. I’ve got the error when i distribute my view files under views folder, /views/view1.py, /views/view2.py and imported some model named table.py in view2.py which happened to be a name of a view in view1.py. So naming the view functions as v_table(request,id) helped.

👤binboavetonik

1👍

Just in case you got the error on your terminal, it is possible that if you stop the server and then run it again, it would work.
On Windows:

ctrl+c

to stop the server
then run the server again:

python manage.py runserver

Cheers.

👤Hesam Moosapour

0👍

Your code is

urlpatterns = [
    url(r'^$', 'myapp.views.home'),
    url(r'^contact/$', 'myapp.views.contact'),
    url(r'^login/$', 'django.contrib.auth.views.login'),
]

change it to following as you’re importing include() function :

urlpatterns = [
    url(r'^$', views.home),
    url(r'^contact/$', views.contact),
    url(r'^login/$', views.login),
]
👤Nishant Soni

0👍

change
register = template.Library()
to
registerr = template.Library()
resovled my issue

👤Shah E Rome Wali

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