[Django]-ManyRelatedManager object is not iterable

Sounds like you are looking for something like

Store.attribute_answers.all()

If you are doing this in a template:

{% for room in study.room_choice.all %}
  {{ room }}
  {% empty %}
  empty list!
{% endfor %}

UPDATE

If you have a through table, you can access the elements in that table (as detailed here) like so (note, you use the through table name, in lowercase, suffixing _set):

{% for roominfo in participant.roomchoicethru_set.all %}
  {{ roominfo.room}} {{ roominfo.telnumber}}
{% endfor %}

all()

For everyone who finds reading code in questions as TL;DR

Instead of query_set.many_to_many

you should use
query_set.many_to_many.all()

Answers are good and I just needed to add a point for easier understanding.You couldn’t query the field where many to many is set because it returns and objects not a list of options.It is better to get the data from the field in your views then pass it to the templates.For example if you have posts model where each post has many to many relations with Tags model.

class Tag(models.Model):
      ""
class Post(models.Model):
      tags = models.ManyToManyField(Tag)

If you tried post.tag.caption it will return this error.You should pass tags as a seperate idintifier in your views.

"post": identified_post,
"post_tags":identified_post.tags.all()

instead of passing only

"post": identified_post

I keep hitting this question whenever this problem comes up. Particularly when trying to actually iterate over a manytomany in a function.

As a template you can do:

array = many_to_many.all()
for x in many_to_many:
  function here

Here busines_type is foreign_key in profile model

pro = Profile.object.filter(user=myuser).first()
business_type = pro.business_type.all()
if business_type:
    b_type = ''
    for b in business_type:
        b_type += str(b.type)+' '
        a = b_type