[Django]-Find object in list that has attribute equal to some value (that meets any condition)

Since it has not been mentioned just for completion.
The good ol’ filter to filter your to be filtered elements.

Functional programming ftw.

####### Set Up #######
class X:

    def __init__(self, val):
        self.val = val

elem = 5

my_unfiltered_list = [X(1), X(2), X(3), X(4), X(5), X(5), X(6)]

####### Set Up #######

### Filter one liner ### filter(lambda x: condition(x), some_list)
my_filter_iter = filter(lambda x: x.val == elem, my_unfiltered_list)
### Returns a flippin' iterator at least in Python 3.5 and that's what I'm on

print(next(my_filter_iter).val)
print(next(my_filter_iter).val)
print(next(my_filter_iter).val)

### [1, 2, 3, 4, 5, 5, 6] Will Return: ###
# 5
# 5
# Traceback (most recent call last):
#   File "C:\Users\mousavin\workspace\Scripts\test.py", line 22, in <module>
#     print(next(my_filter_iter).value)
# StopIteration


# You can do that None stuff or whatever at this point, if you don't like exceptions.

I know that generally in python list comprehensions are preferred or at least
that is what I read, but I don’t see the issue to be honest. Of course Python is not an FP language, but Map / Reduce / Filter are perfectly readable and are the most standard of standard use cases in functional programming.

So there you go. Know thy functional programming.

filter condition list

It won’t get any easier than this:

next(filter(lambda x: x.val == value,  my_unfiltered_list)) # Optionally: next(..., None) or some other default value to prevent Exceptions

A simple example:
We have the following array

li = [{"id":1,"name":"ronaldo"},{"id":2,"name":"messi"}]

Now, we want to find the object in the array that has id equal to 1

1. Use method next with list comprehension

next(x for x in li if x["id"] == 1 )

2. Use list comprehension and return first item

[x for x in li if x["id"] == 1 ][0]

3. Custom Function

def find(arr , id):
    for x in arr:
        if x["id"] == id:
            return x
find(li , 1)

Output all the above methods is {'id': 1, 'name': 'ronaldo'}

Old question but I use this quite frequently (for version 3.8). It’s a bit of syntactic salt, but it has the advantage over the top answer in that you could retrieve a list of results (if there are multiple) by simply removing the [0] and it still defaults to None if nothing is found. For any other condition, simply change the x.value==value to what ever you’re looking for.

_[0] if (_:=[x for x in test_list if x.value==value]) else None

You could do something like this

dict = [{
   "id": 1,
   "name": "Doom Hammer"
 },
 {
    "id": 2,
    "name": "Rings ov Saturn"
 }
]

for x in dict:
  if x["id"] == 2:
    print(x["name"])

Thats what i use to find the objects in a long array of objects.

You could also implement rich comparison via __eq__ method for your Test class and use in operator.
Not sure if this is the best stand-alone way, but in case if you need to compare Test instances based on value somewhere else, this could be useful.

class Test:
    def __init__(self, value):
        self.value = value

    def __eq__(self, other):
        """To implement 'in' operator"""
        # Comparing with int (assuming "value" is int)
        if isinstance(other, int):
            return self.value == other
        # Comparing with another Test object
        elif isinstance(other, Test):
            return self.value == other.value

import random

value = 5

test_list = [Test(random.randint(0,100)) for x in range(1000)]

if value in test_list:
    print "i found it"

I just ran into a similar problem and devised a small optimization for the case where no object in the list meets the requirement.(for my use-case this resulted in major performance improvement):

Along with the list test_list, I keep an additional set test_value_set which consists of values of the list that I need to filter on. So here the else part of agf’s solution becomes very-fast.

For below code, xGen is an anonomous generator expression, yFilt is a filter object. Note that for xGen the additional None parameter is returned rather than throwing StopIteration when the list is exhausted.

arr =((10,0), (11,1), (12,2), (13,2), (14,3))

value = 2
xGen = (x for x in arr if x[1] == value)
yFilt = filter(lambda x: x[1] == value, arr)
print(type(xGen))
print(type(yFilt))

for i in range(1,4):
    print('xGen: pass=',i,' result=',next(xGen,None))
    print('yFilt: pass=',i,' result=',next(yFilt))

Output:

<class 'generator'>
<class 'filter'>
xGen: pass= 1  result= (12, 2)
yFilt: pass= 1  result= (12, 2)
xGen: pass= 2  result= (13, 2)
yFilt: pass= 2  result= (13, 2)
xGen: pass= 3  result= None
Traceback (most recent call last):
  File "test.py", line 12, in <module>
    print('yFilt: pass=',i,' result=',next(yFilt))
StopIteration

If you are looking for an object in an array in Python. You can use the if conditional.

 model_t1 = [0,1,2,3,4]
 model_t2 = [7,8,9,15,14]
 _data = model_t1

 for md in model_t2:
     _data.append(md)

 for p_data in _data:
     if len(p_data['Property']) == 'Value':
        print(json(p_data))

Many great answers already, all dealing with single item lookup, as requested by the OP.

However, if you need to look up multiple items from the list, and your lookup values are unique, e.g. unique ids, it could pay off considerably to convert the list to a dict.

For example:

# dummy data
my_items = [{'id': i, ...} for i in range(1000)]

# convert to dict
my_items_dict = {item['id']: item for item in my_list}

# lookup multiple items
for item_id in long_list_of_ids:
    item = my_items_dict.get(item_id)
    ...