To copy the string “best school” into a new space in memory, you can use different statements to reserve enough space for it. The valid options are:
char newSpace[12];
– This statement declares a character array named “newSpace” and reserves enough space for the string, including the null terminator character. In this case, the size of the array is determined by the length of the string plus 1.char* newSpace = (char*) malloc(12 * sizeof(char));
– This statement dynamically allocates memory using themalloc()
function. It allocates enough space for a character array of size 12. Thesizeof(char)
ensures that the correct amount of memory is allocated.
Here’s an example of how you can use these statements:
<script language="C">
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
char newSpace[12];
strcpy(newSpace, "best school");
printf("Copied string: %s\n", newSpace);
char* dynamicSpace = (char*) malloc(12 * sizeof(char));
strcpy(dynamicSpace, "best school");
printf("Copied string: %s\n", dynamicSpace);
free(dynamicSpace); // Don't forget to free the dynamically allocated memory
return 0;
}
</script>
In this example, the first statement char newSpace[12];
reserves enough space on the stack for the string “best school” and copies it using the strcpy()
function. The result is then printed using printf()
.
The second statement char* dynamicSpace = (char*) malloc(12 * sizeof(char));
allocates memory on the heap using malloc()
. Again, the string “best school” is copied into the allocated space using strcpy()
. Finally, the copied string is printed, and the dynamically allocated memory is freed using free()
to prevent memory leaks.