[Django]-'function' object has no attribute 'as_view'

In my case, the problem was that I tried to use a @decorator on the class-based view as if it was a function-based view, instead of @decorating the class correctly.

EDIT: From the linked page, here is a way to apply @login_required to a class-based view:

from django.contrib.auth.decorators import login_required
from django.utils.decorators import method_decorator

@method_decorator(login_required, name='dispatch')
class ProtectedView(TemplateView):

IngredientCreateView is a function, not a class.

The following line

def IngredientCreateView(CreateView):

should be replace with

class IngredientCreateView(CreateView):

def Some_def_View(CreateView):

#should be replaced with

class SomeClassView(CreateView)

In addition to what is already said here, Check the file name and class name if it is same then you might have to import the class properly.

File name /api/A.py

class A:
//some methods

In your main class

//App main class
from api.A import A

I faced the same problem but this solution worked for me..

in views.py file in viewclass you can use viewsets instead of CreateView

            from rest_framework import viewsets
            class YourClassView(viewsets.ModelViewSet):

in urls.py file you can use this routing pattern

          from django.conf.urls import url
          from rest_framework import routers

          router = routers.DefaultRouter()
          router.register('books',YourClassView)

          urlpatterns = [
               path('', include(router.urls)),
               path('admin/', admin.site.urls)
            ]